π
r
2
a
x
2
+
b
x
+
c
=
0
x
=
-
b
±
b
2
-
4
a
c
2
a
A
=
x
y
z
w
∫
1
t
ⅆ
x
x
x
1
t
1
x
a
x
2
+
b
x
+
c
=
0
2
x
×
-
1
16
+
−
5
2
=
24
15
16
E
=
m
c
2
{
[
a
+
b
+
c
)
-
d
}
a
+
b
8.44
x
+
55
y
=
0
3.1
x
-
0.7
y
=
-
1.1
sin
x
+
5
x
5
\sin x + 5
x
+
y
x
3
64
4
x
3
+
1
x
5
x
+
1
−
1
3
f
(
a
)
=
1
2
π
i
∮
f
(
z
)
z
−
a
d
z
cos
(
θ
+
φ
)
=
cos
(
θ
)
cos
(
φ
)
−
sin
(
θ
)
sin
(
φ
)
(
4
x
1
4
)
(
9
x
)
1
2
log
2
x
ln
e
=
1
V
=
4
3
π
r
3
x
1
+
x
2
−
x
3
sin
2
x
+
cos
2
y
=
1
∇
→
⋅
F
→
=
(
∂
F
z
∂
y
−
∂
F
y
∂
z
)
i
+
(
∂
F
x
∂
z
−
∂
F
z
∂
x
)
j
+
(
∂
F
y
∂
x
−
∂
F
x
∂
y
)
k
A
B
C
△
A
B
⌒
A
B
←
10
∵
5
l
i
m
x
→
∞
f
(
x
)
A
=
4
π
r
2
sin
A
=
A
C
cos
A
=
B
C
sin
−
1
x
=
a
r
c
s
i
n
x
tan
θ
=
A
B
cot
A
=
B
A
sec
A
=
C
A
csc
A
=
C
B
xx
yy
π
r
2
a
x
2
+
b
x
+
c
=
0
x
=
-
b
±
b
2
-
4
a
c
2
a
A
=
x
y
z
w
∫
1
t
ⅆ
x
x
x
1
t
1
x
a
x
2
+
b
x
+
c
=
0
2
x
×
-
1
16
+
−
5
2
=
24
15
16
E
=
m
c
2
{
[
a
+
b
+
c
)
-
d
}
a
+
b
8.44
x
+
55
y
=
0
3.1
x
-
0.7
y
=
-
1.1
sin
x
+
5
x
5
\sin x + 5
x
+
y
x
3
64
4
x
3
+
1
x
5
x
+
1
−
1
3
f
(
a
)
=
1
2
π
i
∮
f
(
z
)
z
−
a
d
z
cos
(
θ
+
φ
)
=
cos
(
θ
)
cos
(
φ
)
−
sin
(
θ
)
sin
(
φ
)
(
4
x
1
4
)
(
9
x
)
1
2
log
2
x
ln
e
=
1
V
=
4
3
π
r
3
x
1
+
x
2
−
x
3
sin
2
x
+
cos
2
y
=
1
∇
→
⋅
F
→
=
(
∂
F
z
∂
y
−
∂
F
y
∂
z
)
i
+
(
∂
F
x
∂
z
−
∂
F
z
∂
x
)
j
+
(
∂
F
y
∂
x
−
∂
F
x
∂
y
)
k
A
B
C
△
A
B
⌒
A
B
←
10
∵
5
l
i
m
x
→
∞
f
(
x
)
A
=
4
π
r
2
sin
A
=
A
C
cos
A
=
B
C
sin
−
1
x
=
a
r
c
s
i
n
x
tan
θ
=
A
B
cot
A
=
B
A
sec
A
=
C
A
csc
A
=
C
B
xx
yy